We have the three lines 4x – y – 9 = 0 , 3x – 2y – 3 = 0 and x – y = 0.

First, let us find their points of intersection.

We can write 4x – y – 9 = 0 as y = 4x – 9

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We have the three lines 4x – y – 9 = 0 , 3x – 2y – 3 = 0 and x – y = 0.

First, let us find their points of intersection.

We can write 4x – y – 9 = 0 as y = 4x – 9

Substitute this in 3x – 2y – 3 = 0

=> 3x – 2(4x – 9) – 3 =0

=> 3x – 8x + 18 – 3 = 0

=> -5x = -15

=> x = 3

y = 4x – 9 = 3

Now we see that (3 , 3) also lies on x – y = 0

Therefore all the three lines intersect at the same point. So they do not form a triangle.

**The three lines do not form a triangle.**